[CheckIO/Electronic Station] acceptable-password-iii

1. Problem:  https://py.checkio.org/en/mission/acceptable-password-iii/
2. My solution

def is_acceptable_password(password: str) -> bool:
    # your code here
    if len(password) < 6: return False
    else:
        list_boolen = [ x.isnumeric() for x in list(password)]
        if True in list_boolen : 
            if False in list_boolen: return True
        
        return False