1. Problem: https://py.checkio.org/en/mission/pangram/
2. My solution
python
접기def check_pangram(text): ''' is the given text is a pangram. ''' # your code here List = [] pangram = "" for character in list(text.lower()): if ord(character) < 123 and ord(character) > 96: List.append(character) for char in sorted(set(List)): pangram +=char if pangram == "abcdefghijklmnopqrstuvwxyz": return True else: return False
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