[CheckIO] Popular words

Problems: py.checkio.org/en/mission/popular-words/

My solution

python

접기

def popular_words(text: str, words: list) -> dict:
    # your code here
    
    counts = []
    for f_word in words:
        counting_numbers = 0
        for match_words in (text.lower()).split():
            if match_words == f_word: counting_numbers = counting_numbers + 1
        counts.append(counting_numbers)
    
    return dict(zip(words, counts))
 
 
if __name__ == '__main__':
    print("Example:")
    print(popular_words('''
When I was One
I had just begun
When I was Two
I was nearly new
''', ['i', 'was', 'three', 'near']))
 
    # These "asserts" are used for self-checking and not for an auto-testing
    assert popular_words('''
When I was One
I had just begun
When I was Two
I was nearly new
''', ['i', 'was', 'three', 'near']) == {
        'i': 4,
        'was': 3,
        'three': 0,
        'near': 0
    }
    print("Coding complete? Click 'Check' to earn cool rewards!")

 

A good solution that I see

python

접기

def popular_words(text, words):
    lower_count = text.lower().split().count
    return {word: lower_count(word) for word in words}